Utilizing TypeScript's generic constraints for multiple primitive data types

Consider the following function:

myFunc(object: string | null): string | null {}

The desired behavior for this function is to return type string when the object parameter is of type string, and return type string | null when the object parameter is of type string | null.

Attempts have been made as follows:

myFunc<T extends string | null>(object: T): T {
    return "returnValue"; //Type '"returnValue"' is not assignable to type 'T'.
}

and

myFunc<T extends string & null>(object: T): T {
    return "returnValue"; //Type '"returnValue"' is not assignable to type 'T'.
}

Both attempts result in the same compile error. The correct syntax has yet to be discovered.

Answer №1

It's quite surprising that I am going to propose using overloads in this scenario, especially since I usually advocate for avoiding them whenever possible... but employing an overload could effectively model this situation!

class Example {
    myFunc(obj: string): string;
    myFunc(obj: string | null): string | null;
    myFunc(obj: string | null): string | null {
        return "returnValue";
    }
}

function test(a: string | null, b: string) {
    const example = new Example();

    // resultA: string | null
    const resultA = example.myFunc(a);

    // resultB: string
    const resultB = example.myFunc(b);
}

In the given example, the return types are aligned with the input types, ensuring that resultA and resultB have the correct types, assuming strict null checks are enabled.

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