Ways to define a data structure where all elements adhere to the same data type

Here is a simple example:

typedef Bar = { x: number; y: boolean }
type Foo = { [key: string]: Bar }

const foo: Foo = {
  baz: { x: 3, y: true }
}

// This will pass without any issues
console.log(foo['baz'])

// Error message stating: Property 'baz' does not exist on type '{ [key: string]: { x: number; y: boolean; }; }'.
console.log(foo.baz)

I am looking for the last line to be able to check the type correctly and have the type of foo.baz labeled as Bar. If index signatures are not suitable for achieving this type of definition, what would be the correct approach? Is it even feasible?

Answer №1

Think of index signatures as a tool similar to a dictionary. To access them, you must use an index. This method is implemented to clearly indicate that the absence of a key is a valid possibility.

Solution

If you are certain that a member will always be present, annotate it accordingly like so:

type Foo = { [key: string]: Bar, baz:Bar }

Answer №2

If you are searching for specific attributes, consider taking this approach:

interface Foo2 {
    baz: Bar;
}

const foo2: Foo2 = {
    baz: { x: 3, y: true }
}

console.log(foo2.baz); // functions correctly 

Revision

If the attributes are not predetermined, you will need to define the type in your query. In such a case, accessing values directly as properties may not be possible due to the unpredictable keys. The compiler is unable to confirm the existence of the specified property name, which could result in issues like mistakes (e.g., using bar instead of baz)

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