Ways to verify the presence of my property within a specific type

When it comes to TypeScript, we have the ability to declare partial types. But what happens when we need to check if a property is within the keys of a type? Let's explore.

interface Car {
   Brand: string;
   Model: string;
}

type KeyofCar = keyof Car; // Brand, Model

if('Brand' is in KeyofCar) {
   something...
} // This is just pseudocode and won't work as intended

Is there a solution to this problem?

Answer №1

It seems like you already have the knowledge that 'Brand' is part of the Car object at compile time. So, why would you need to check for it?

If the type is not fully known, perhaps in a type argument scenario, then attempting something like this could be considered...

function<T>(foo: T) {
  // This won't work since 'keyof' doesn't exist in runtime environments
  if('bar' in keyof T) {
    // do something...
  }
}

Instead of comparing against keyof T, try a different approach like below...

interface Car {
  Brand: string;
  Model: string;
}

interface Bus {
  Passengers: number;
  Color: string;
}

function(foo: Car | Bus) {
  if('Brand' in foo) {
    // It's a Car
  } else {
    // It's a Bus
  }
}

If working with keys is your goal, consider this alternative...

type CarKey = keyof Car;
const carKeys: CarKey[] = ['Brand', 'Model'];

function(key: string) {
  if(carKeys.includes(key)) {
    // perform action
  }
}

To ensure you have all keys covered, here's a more thorough method...

type CarKey = keyof Car;
const carKeys = Object.keys({
    Brand: null, 
    Model: null
} satisfies Record<CarKey, null>) as Array<keyof Car>;

function isKeyOfCar(key: string): key is CarKey {
    return carKeys.includes(key);
}

This way, any future changes to the Car type will prompt updates to these key checks.

Answer №2

Currently, there is no built-in way in Typescript to validate certain properties at runtime. However, a potential workaround involves creating a Record object and utilizing its keys for validation.

interface Animal {
   Species: string;
   Habitat: string;
}

const animalRecord: Record<keyof Animal, boolean> = {
  Species: true,
  Habitat: true
}

if (animalRecord['Species']) {
  do something...
}

The use of a Record is essential as any changes made to the interface must also be reflected in the Record declaration to prevent compilation errors. This approach helps maintain consistency in property checks as the underlying interface evolves.

Answer №3

const CheckProperty<T extends {[key:string]:any}, PropertyName extends string> = T[PropertyName] ? true : false;
//Example
const HasProperty = CheckProperty<{name:string; age:number},"age">;
//HasProperty is true

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