What is the best way to filter or choose tuples based on their inclusion in a certain group

I am working with a tuple object that contains nested tuples.

const foo = [
  { id: 't1', values: ['a', 'b'] },
  { id: 't2', values: ['a', 'c'] },
  { id: 't3', values: ['b', 'c'] },
] as const;

My goal is to filter this data based on tuple values while also specifying the type.

There is a function that provides the correct runtime value but results in a type error:

var objsWithA = foo.filter(({ values }) => values.includes('a'));

Using as any or as never to bypass the type error does not properly eliminate t3:

var objsWithA = foo.filter(({ values }) => values.includes('a' as never));

Is there a way to match the resulting type with the returned value?

[
  { id: 't1', values: ['a', 'b'] },
  { id: 't2', values: ['a', 'c'] },
]

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Answer №1

When working with TypeScript, you can utilize the array method filter() to narrow down the type of the resulting array using a specific call signature:

interface ReadonlyArray<T> {
  filter<S extends T>(
    predicate: (value: T, index: number, array: readonly T[]) => value is S,
    thisArg?: any
  ): S[];
}

This requires the use of a custom type guard function as the `predicate`, ensuring it returns a type predicate.

However, TypeScript does not automatically infer type predicates from function implementations. Even simple cases like `x => typeof x === "string"` are not supported yet, as indicated in microsoft/TypeScript#38390.

For scenarios where direct calls such as

({values})=>values.includes("a")
are used, even established array methods like includes() do not act as type guards. An issue requesting this feature has been closed due to the complexity involved (microsoft/TypeScript#31018).

To work around this limitation, you may need to write explicit custom type guard functions and incorporate them sensibly when calling filter(). One approach involves generating a type guard function for a broader case:

const objPropHasArrayContainingStringLiteral = <K extends string, T extends string>(propName: K, stringLiteral: T) => <U extends Record<K, readonly string[]>>(obj: U): obj is (
       U extends Record<K, readonly (infer V extends string)[]> ? 
       [T] extends [V] ? U : never : never
    ) => obj[propName].includes(stringLiteral);

By using

objPropHasArrayContainingStringLiteral(propName, stringLiteral)
, you create a type guard function that verifies if an object contains an array property at propName with the specified stringLiteral.

The implementation employs a distributive conditional type to filter a union type U based on a property match criterion.

In practice, utilizing the generated type guard function may resemble something like

objPropHasArrayContainingStringLiteral("values", "a")
, enabling you to filter arrays accordingly:

const objsWithA = foo.filter(objPropHasArrayContainingStringLiteral("values", "a"));

While powerful, it's essential to remember that TypeScript doesn't verify custom type guard function logic. Therefore, caution must be exercised to ensure accurate filtering results.

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