What is the best way to limit a property and template literal variable to identical values?

Instead of giving a title, I find it easier to demonstrate what I need:

type Foo = "bar" | "baz";

interface Consistency {
    foo: Foo;
    fooTemplate: `${Foo} in a template`;
}

// This should compile (and it does)
const valid1: Consistency = {
    foo: "bar",
    fooTemplate: "bar in a template",
}

const valid2: Consistency = {
    foo: "baz",
    fooTemplate: "baz in a template",
}

// This should NOT compile (but it does)
const invalid1: Consistency = {
    foo: "bar",
    fooTemplate: "baz in a template",
}

const invalid2: Consistency = {
    foo: "baz",
    fooTemplate: "bar in a template",
}

You can experiment with this example here. I attempted to modify Consistency to

interface Consistency {
    foo: Foo;
    fooTemplate: `${foo} in a template`; //lowercase foo
}

but that didn't work. Is there a way to make the compiler throw an error in the invalid cases?

Answer №1

If you want to create a union type from all valid sub-types, you can achieve this by using a mapped type in TypeScript:

type Consistency  = {
    [Key in Foo]: {
        foo: Key;
        fooTemplate: `${Key} in a template`;
    }
}[Foo]

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