Is there a way to extract the name of an argument from one type and use it in another type? For example, is it possible to achieve something like this:
type F_v1 = (name: number) => boolean;
type A = ["name", number];
//type F_v2 = (A[0]: A[1]) => boolean; // this is not really allowed
(Assuming that argument names are embedded within function types - TypeScript IDEs often read argument names from any function type. Even using (...as: A) => boolean results in argument names like "as_0".)
Using labeled tuples (documentation) and array spread syntax, it is possible to achieve something similar:
type F_v1 = (name: number) => boolean;
type A = [name: number];
type F_v2 = (...args: A) => boolean;
The Parameters utility type can also be useful for extracting the parameter type from a function (documentation):
type F_v3 = (...args: Parameters<F_v1>) => boolean;
Functions like F_v2 and F_v3 have the same named parameters as F_v1:
const test= (f1: F_v1, f2: F_v1, f3: F_v3) => {
type T1 = typeof f1 // (name: number) => boolean
type T2 = typeof f2 // (name: number) => boolean
type T3 = typeof f3 // (name: number) => boolean
}
It's worth noting that using f3 may result in different types of errors, referencing args instead of name.
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