What is the best way to remove a void type from a union type?

Hey there everyone, I have a custom generic type called P that is defined as

P extends Record<string, unknown> | void

I am looking to create an exists function

export class Parameters<P extends Record<string, unknown> | void> {
        private params: P
        constructor(params: P) {
                this.params = params 
        }
        public exists(field: keyof P): boolean {
                return field in this.params
        }
}

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However, I encountered a compilation error when running tsc because it cannot be applied to the void type. Any suggestions on how to resolve this issue inside my exists function?

tsc Typescript version 4.9.3 Thanks!

https://i.sstatic.net/sG8m2.png

Answer №1

Before proceeding, ensure that the parameters are not undefined

export class Parameters<P extends Record<string, unknown> | void> {
    params!: P
    public exists(field: P): boolean {
        return this.params && field in this.params
    }
}

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