What is the proper way to inform TypeScript that the method in my subclass will be returning a distinct type?

I currently have a class structure that resembles the following:

class BasicType {
    coerce(value) {
        return String(value);
    }
    read(value) {
        return this.coerce(value);
    }
}

The coerce method consistently returns a string, while the read method may return various types depending on the subclass. For instance:

class FloatType extends BasicType {
    read(value) {
        return Number(super.read(value));
    }
}

I am attempting to implement this in TypeScript but am encountering difficulties. I believe I need to utilize generics for this functionality, but my initial attempts were not successful.

class BasicType<T = string> {
    coerce(value: any): string {
        return String(value);
    }
    read(value: any): T {
        return this.coerce(value);
        // Type 'string' is not assignable to type 'T'.
        //   'T' could be instantiated with an arbitrary type unrelated to 'string'
        // ts(2322)
    }
}

class FloatType<T = number> extends BasicType<T> {
    read(value: any): T {
        return Number(super.read(value));
        // Type 'number' is not assignable to type 'T'.
        //   'T' could be instantiated with an arbitrary type unrelated to 'number'.
        // ts(2322)
    }
}

This becomes more complex when subclassing the subclass.

class IntegerType<T = number> extends FloatType<T> {
    read(value: any): T {
        return Math.floor(super.read(value));
        // `return`
        // Type 'number' is not assignable to type 'T'.
        //   'T' could be instantiated with an arbitrary type unrelated to 'number'.
        // ts(2322)
        // `super.read(value)`
        // Argument of type 'T' is not assignable to parameter of type 'number'.
        // ts(2345)
    }
}

What mistakes am I making here? How can I instruct TypeScript that FloatType#read returns a number so it can be used in IntegerType#read as intended?

Answer №1

From my perspective, the BasicType class serves as an abstract base class that is not meant to be instantiated on its own.

abstract class BasicType<T = string> {
    coerce(value: any): string {
        return String(value);
    }
    abstract read(value: any): T;
}

class FloatType extends BasicType<number> {
    read(value: any) {
        return Number(this.coerce(value));
    }
}

class IntegerType extends FloatType {
    read(value: any) {
        return Math.floor(super.read(value));
    }
}

class StringType extends BasicType<string> {
    read(value: any) {
        return this.coerce(value);
    }
}

TS Playground

Answer №2

One limitation in method overriding is that we cannot change the method type. However, it is possible to set the parent method type to any data type:

class BasicType {
    coerce(value) {
        return String(value);
    }
    read(value): any {
        return this.coerce(value);
    }
}

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