What is the reason behind the lack of covariance in an interface when using a type of T[keyof T]?

I'm attempting to enable type covariance so that Type<Cat> can be treated as a Type<Animal>, for instance, treating a list of Cats as a list of Animals. However, using the type T[keyof T] in a method within the Type interface seems to hinder this behavior.

type Animal = {
    legs: boolean;
}

type Dog = Animal & {
    golden: boolean;
}

// Demonstrates covariance
interface Comparer<T> {
    compare(a: T, b: T): number;
}

// This is valid
declare let animalComparer: CovariantComparer<Animal>;
declare let dogComparer: CovariantComparer<Dog>;

animalComparer = dogComparer;
dogComparer = animalComparer;  

// This does not work
interface NonCovariantComparer<T> {
    compare(a: T, b: T[keyof T]): number;
}

declare let animalComparer2: NonCovariantComparer<Animal>;
declare let dogComparer2: NonCovariantComparer<Dog>;

animalComparer2 = dogComparer2; //typeerror
dogComparer2 = animalComparer2; //typeerror

Is there a way to make this setup function as desired? If not, why is it impossible and are there effective patterns to overcome this hurdle? Thank you!

Note: I am operating under the assumption that making the object a method will make it bivariant

Typescript playground example

Answer №1

Introducing a generic type U extends T in the compare() method of the interface seems to successfully resolve the issues:

type Animal = {
    legs: boolean;
}

type Dog = Animal & {
    golden: boolean;
}

interface CovariantComparer<T> {
    compare<U extends T>(a: T, b: U[keyof T]): number;
}

declare let animalComparer: CovariantComparer<Animal>;
declare let dogComparer: CovariantComparer<Dog>;

animalComparer = dogComparer;
dogComparer = animalComparer;

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