Breaking down type arguments in function declarations in TypeScript

Exploring a function that reverses a pair, I am seeking to define aliases for both the input and output in a way that can be utilized within the function itself and its type signature.

function reverse<A, B>([a, b]: [A, B]): [B, A] {
  return [b, a];
}

I am interested in passing input and output types as arguments to 'reverse,' making it more intuitive for the caller compared to using A and B which are more internal details.

function reverse<I extends [infer A, infer B], O implements [B, A]>([a, b]: I): O {
  return [b, a];
}

In an attempt to experiment with this concept, I made the following modifications. However, it does not work as intended since the output is not guaranteed to extend [B, A].

function reverse<A, B, I extends [A, B], O extends [B, A]>([a, b]: I): O {
  return [b, a];
}

Are there any alternative solutions to make this approach successful?

Answer №1

Instead of creating new type aliases for Tuples, why not simply use existing ones?

type Pair<X, Y> = [X, Y];

function swap<A, B>([a, b]: Pair<A, B>): Pair<B, A> {
    return [b, a];
}

Another approach could be:

type Pair<X, Y> = [X, Y];
type ReversedPair<X, Y> = [Y, X];

function reverse<A, B>([a, b]: Pair<A, B>): ReversedPair<A, B> {
    return [b, a];
}

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