Can a type be formed with a generic type as the rest parameter?

After exploring the question about implementing a choice of index type on an interface Defining a choice of index type on an interface

Now, I am tasked with creating a sequence of elements. Typically it would look like element1 & element2, but because I'm converting an XSD schema, I want it to align 1-to-1 to prevent confusion for new TypeScript developers.

Currently, this is the existing type structure:

type Object_Type<T> = { [P in keyof T]: T[P] };
type Sequence<A, B = {}, C = {}, D = {}, E = {}, F = {}, G = {}, H = {}, I = {}, J = {}, K = {}, L = {}, M = {}, N = {}> =
    Object_Type<A>
    & Object_Type<B>
    & Object_Type<C>
    & Object_Type<D>
    & Object_Type<E>
    & Object_Type<F>
    & Object_Type<G>
    & Object_Type<H>
    & Object_Type<I>
    & Object_Type<J>
    & Object_Type<K>
    & Object_Type<L>
    & Object_Type<M>
    & Object_Type<N>;

This type can be utilized as follows:

const sequence: Sequence<{name: string}, {age: number}> = {
    name: "John",
    age: 999
};

However, manually defining each generic parameter and assigning default values seems excessive. Is there a way to simplify it like this?

type Sequence<...T> = Object_Type<...T>;

Answer №1

In TypeScript, there isn't native support for variadic kinds like discussed here, so using the exact syntax of Sequence<...T> won't directly work. However, you can achieve similar functionality by utilizing a tuple type approach as shown in

Sequence<[{name: string}, {age: number}]>
. This involves mapping the tuple with Object_Type, transforming it into a union by referencing its number property, and then converting the union to an intersection as described here.

type Object_Type<T> = { [P in keyof T]: T[P] };
type UnionToIntersection<U> =
  (U extends any ? (k: U) => void : never) extends ((k: infer I) => void) ? I : never;
type Sequence<T extends any[]> = 
  UnionToIntersection<{ [K in keyof T]: Object_Type<T[K]> }[number]>;

const sequence: Sequence<[{ name: string }, { age: number }]> = {
  name: "Alice",
  age: 30
};

This solution is effective, although potential edge cases may arise depending on your specific types (especially if they are unions themselves). It's worth considering the purpose of using Object_Type within Sequence – what benefits does Sequence<A,B,C> offer over A & B & C? Providing more context could lead to a simpler or more optimized solution for your scenario.

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