This scenario applies to both scenarioOne and scenarioTwo:
type OptionalType = {y?: boolean};
const scenarioOne: OptionalType = { y: undefined };
const scenarioTwo: OptionalType = { };
I am seeking a solution where only scenarioTwo would pass the type check.
Is there a method to define OptionalType in such a way that enforces this requirement?
Appreciate your help!
It is possible to differentiate between { x: boolean | undefined } and { x?: boolean }. Although { x: boolean | undefined } can be assigned to { x?: boolean }, the reverse is not true.
However, a object literal with type { x: undefined } will always be assignable to {x?: boolean } regardless of compiler settings.
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