Ensuring Type Compatibility Between Classes and Object Literals in TypeScript

When working with TypeScript, it is important to note that an object literal can be assigned to a class typed variable as long as the object provides all properties and methods required by the class.

class MyClass {
  a: number;
  b: string;
}

// The compiler will not raise an error
const instance: MyClass = { a: 1, b: '' };

// Even if the object has additional properties, the compiler will not complain
const literal = { a: 1, b: '', c: false };
const instance2: MyClass = literal;

However, there may be instances where you want to prevent such assignments for two main reasons:

  1. The expression instance instanceof MyClass should evaluate to true;
  2. Avoiding the assignment of objects with extra properties (as seen above).

To enforce stricter type checking similar to how interfaces work in TypeScript, one might wonder if there is a way to restrict this behavior. Is there a solution to achieve this?

Answer №1

According to information from the TypeScript documentation, it appears that the behavior you are experiencing is as expected:

Type compatibility in TypeScript is established through structural subtyping, which relates types solely based on their members.

Essentially, if two types have matching structures, objects of those types should be interchangeable.

An ongoing feature request on microsoft/TypeScript#29063 seeks a way to differentiate between class instances and object types with identical structures, but this distinction is not currently supported by the language.

Solution: Utilizing private members

In practice, incorporating private members into a class (which is commonly done) enhances the effectiveness of type checking according to your expectations.

class MyClass {
  a: number;
  b: string;
  private c: number;
}

// "Property 'c' is missing in type '{ a: number; b: string; }' but required in type 'MyClass'."
const instance: MyClass = { a: 1, b: '' };

// "Property 'c' is private in type 'MyClass' but not in type '{ a: number; b: string; c: number; }'"
const literal: MyClass = { a: 1, b: '', c: 3 };

class OtherClass {
  a: number;
  b: string;
  private c: number;
}

// "Types have separate declarations of a private property 'c'"
const otherClass: MyClass = new OtherClass();

Answer №2

It seems like there might be some confusion regarding the question, but based on the code provided, it appears that:

In the second part of your assignment, the variable literal is not specifically defined as type MyClass.

const literal = { a: 1, b: '', c: false };

Therefore, you are essentially creating a constant variable with certain values.

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