Here's a snippet of TypeScript code that compiles successfully:
let testVar: any;
const testFunc: () => number = () => {
return testVar;
};
Why does this code compile without errors? What is the reasoning behind it?
Here's a snippet of TypeScript code that compiles successfully:
let testVar: any;
const testFunc: () => number = () => {
return testVar;
};
Why does this code compile without errors? What is the reasoning behind it?
One interesting feature of TypeScript is that the compiler does not perform type checking for variables declared with the `any` type. This means that `any` can be used as a valid type for all variables in TypeScript. For instance,
let x: number = 0;
let y: any = "this is a string";
x = y;
The code above will compile successfully without any errors because TypeScript recognizes that the type of `y` is `any`, allowing it to be assigned to a variable with any type of value (such as string, number, boolean, etc).
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