Providing the type for an abstract class implementation: A guide

Is there a way to define a type for "any class that implements this abstract class"?

For instance:

// LIBRARY CODE
abstract class Table {
  static readonly tableName: string;
}
type TableConstructor = typeof Table;
// type TableConstructor = (new (...args: never) => Table);
const createORM = (tables: Array<TableConstructor>) => {
  return {
      executeQuery() {
        // What should be the type of the "tables" array 
        // to accommodate both of the following two lines
        console.log(tables[0].tableName)
        return new tables[0]();
        //     ~~~~~~~~~~~~~~~~
        // Cannot instantiate an abstract class
      }
  }
}


// EXAMPLE USER CODE
class Foo implements Table {
  static get tableName() {
      return 'foo';
  }
}
const orm = createORM([Foo]);

TypeScript Playground Example Link

Answer №1

interface TableConstructor {
  new (...args: never): Table;
  readonly tableName: string;
}

or you can also use

type TableConstructor = (new (...args: never) => Table) & Omit<typeof Table, never>;

Here is the example with this implementation

Answer provided on the TypeScript discord:

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