When it comes to traditional functions and methods, this
acts as a read-only parameter passed to the function by the calling code. You can find more information on this topic here. Essentially, when the function is executed, this
refers to whatever the caller has specified explicitly or implicitly.
In TypeScript, using the this
pseudo-parameter allows you to specify the type that this
will have when the function is invoked. For example, in the DB
interface, the filterUsers
method specifies that this
will be a reference to a User
object during the callback.
You don't need to restate this type information in your callback function because TypeScript can infer it from the DB
interface's declaration:
const db = getDB();
const admins = db.filterUsers(function() {
return this.admin;
});
In one of the comments, you asked:
How does the function become bound to a specific User
instance here?
The logic inside the filterUsers
method ensures that when the callback is called, it sets the context (this
) to a user object. This might involve using Function.prototype.call
or Function.prototype.apply
:
// Hypothetical snippet for a `filterUsers` method:
filterUsers(callback: (this: User) => boolean): User[] {
const filtered = this.users.filter(user => callback.call(user));
return filtered;
}
Using .call
or .apply
allows you to explicitly define the context for a function call.
It's worth mentioning that defining DB
's filterUsers
method in this way is not typically how interfaces would handle such behavior. It would be more conventional for the user to be passed as a regular argument, similar to how Array.prototype.filter
works. However, this unconventional approach is used in documentation examples for explanatory purposes.