The distribution of intersection types is not properly handled by Typescript's array.map function

My array is of type object[] & Tree[], but when using arr.map(child => ...), the type of child is inferred as object instead of object & Tree.

Is there a way to avoid this without additional casting?

It's worth noting that Tree extends object, but TypeScript doesn't recognize this and merge the two parts of the intersection type.

EDIT - Here's a minimal reproducible example:

While this example is contrived, it is based on another recent question I had: Transform a typescript object type to a mapped type that references itself

interface BasicInterface {
    name: string;
    children: object[];
}

function getBasic<T extends object>(input: T): BasicInterface {
    return input as BasicInterface;
}

export const basicTree = getBasic({
    name: 'parent',
    children: [{
        name: 'child',
        children: []
    }]
});

In this code snippet, "basicTree" has an inferred type. While I have defined BasicInterface in this example, in reality, it is generated automatically and I haven't found a way to programmatically generate a recursive interface.

I want to add back the recursive type of children as defined in the original interface.

Instead of completely redefining BasicInterface in the code (which could be cumbersome), I am attempting to "enhance" the type definition of basicTree with the correct recursive definition.

However, this approach falters when trying to determine the type of children. Is there a simpler solution available?

type RestoredInterface = typeof basicTree & {
    children: RestoredInterface[]
};

function getTree(basic: BasicInterface): RestoredInterface {
    return basic as RestoredInterface;
}

const restoredTree = getTree(basicTree);

const names = restoredTree.children.map(child => child.name);

Answer №1

After some experimentation, I stumbled upon a peculiar solution. Simply rearranging the declaration order seems to do the trick:

type RestoredInterface = {
    children: RestoredInterface[]
} & typeof basicTree;

Update: For further insight, check out this explanation.

An improved approach could look something like this:

type RestoredInterface = Omit<typeof basicTree, 'children'> & {
    children: RestoredInterface[]
};

For a hands-on demonstration, visit the TypeScript Playground

Answer №2

After a keen observation made by jcalz, it has been noted that extending the original interface is quite achievable. Initially, there was confusion due to its programmatic definition, but this can easily be resolved by assigning a name first:

type CustomTreeInterface = typeof customTree;

interface ExtendedInterface extends CustomTreeInterface {
    children: ExtendedInterface[]
};

const extendedTree = generateTree(customTree);

const labels = extendedTree.children.map(child => {
    // Child falls under the type ExtendedInterface
});

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