The predicate "adds" is applied to the type rather than substituting it

In my class, I am using a generic type to represent the known elements of its map, as shown below:

abstract class Component { ... }

class Test<Known extends Component[]> {
    components: Map<string, Component> ...

    has<C extends Component>(comp: C): this is Test<[...Known, C]> {
       ...
    }
}

I was hoping to utilize Test.has() to change its type when checking for available components, but it seems to append to the type instead of replacing it:

// test is Test<[AComp, BComp]>, all good so far
const test = new Test<[AComp, BComp]>();

const comp = new CComp();

if (sometest.has(comp)) {
    // now test becomes "Test<[AComp, BComp]> & Test<[AComp, BComp, CComp]>"
}

Essentially, test.has() correctly gets the type, but instead of replacing it, it combines them with an "&".

I understand that TypeScript handles it this way because it doesn't recognize that the second type extends the first, treating them as distinct entities.

Is there a way to communicate to the engine that the second type extends the first, if at all possible?

Edit with Reproducible example:

abstract class Component {
}
class AComp extends Component {
  aValue = 1;
}
class BComp extends Component {
  bValue = 3;
}
type ClassOf<C extends Component> = new (...args: any[]) => C;
type TestGetResult<C extends Component, K extends Component[]> = C extends K[number] ? C : (C | undefined); 
class Test<K extends Component[]> {
  components = new Map<string, Component>();
  constructor(components: Component[]) {
    components.forEach(comp => this.components.set(comp.constructor.name, comp));
  }

  has<C extends Component>(comp: ClassOf<C>): this is Test<[...K, C]> {
    return [...this.components.keys()].includes(comp.name);
  }

  get<C extends Component>(comp: ClassOf<C>): TestGetResult<C, K> {
    return this.components.get(comp.name) as TestGetResult<C, K>; 
  }
}
// This class simulates us getting the Test instances from somewhere else in the code, their type is not immediately known when we return them but by
// using .has() we can infer some of it
class SomeStore {
  list: Test<any>[] = [];
  add(test: Test<any>) { this.list.push(test); }

  getTestWithSomeComponent<C extends Component>(comp: ClassOf<C>): Test<[C]> {
    for (let test of this.list) {
      if (test.has(comp)) {
        return test;
      }
    }
    throw new Error('No test found');
  }
}
///////////////////////////////////////////////////////////////////////////////////////
const store = new SomeStore();
const test1 = new Test<[AComp, BComp]>([new AComp(), new BComp()])
store.add(test1);                                                
                                                                
const testAfterGet = store.getTestWithSomeComponent(AComp);
if (testAfterGet.has(BComp)) {
  const a = testAfterGet.get(AComp);
  // Here is the issue
  const b = testAfterGet.get(BComp) // at this point, testAfterGet has the 'and' type
  console.log(a.aValue); 
  console.log(b.bValue); // b should not be undefined
}

Answer №1

When using a custom type guard method that returns this is X, it is important to ensure that the type of X is compatible with the type of the object being checked. Type guard functions and methods are designed to narrow types, not alter them arbitrarily. The intersection of this & X inherently narrows the type of this, making it a reliable approach.

If this approach is not suitable, alternatives like Extract<X, this> with the Extract utility type can be considered. However, if X cannot be assigned to this, the result might be never, which is likely not the intended outcome.

In scenarios where Test<[AComp, BComp]> cannot be assigned to Test<[AComp]>, a direct solution may be unattainable.

Although intersections typically achieve the desired outcome, they can lead to what appears to be an overload in methods. To adjust the order of overloads without sacrificing functionality, explicitly specifying the return type as the reverse intersection (X & this instead of this & X) can be beneficial.

By implementing this adjustment, the code can successfully handle situations like the provided example with Test<[AComp, BComp]> and

Test<[AComp]>.</p>
<p>It is recommended to refactor code so that <code>Test<X>
extends Test<Y> only when X and Y share a clear and simple relationship. The current utilization of tuple types, which consider the order of types, may not align with the actual requirements of the codebase, especially since the constructor of Test<K> does not interact with K. Refactoring for this purpose is beyond the scope of the original question.

Playground link to code

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