Looking for a solution similar to: how to reference all parameters except first in typescript
This time, I need to access all parameters except the last one.
The solution provided in that question didn't work for my specific case.
Any suggestions on how to achieve this?
To achieve this functionality, one can utilize an inferred rest type approach, albeit with some complexity due to trailing optional arguments that disrupt the rest-type matching process. A solution to this issue involves enclosing the parameters in non-optional singleton tuples, which can then be unwrapped to obtain the initial parameters.
type Wrap<T> = {[K in keyof T]-?: [T[K]]}
type Unwrap<T> = {[K in keyof T]: Extract<T[K], [any]>[0]}
type InitialParameters<F extends (...args: any) => any> =
Wrap<Parameters<F>> extends [...infer InitPs, any] ? Unwrap<InitPs> : never
const f1 = (str: string, n?: number, b?: boolean) => {}
const f2 = (to: string, overrides?: number) => {}
type Test1 = InitialParameters<typeof f1>
// [str: string, n: number | undefined]
type Test2 = InitialParameters<typeof f2>
// [to: string]
Initially,
reverse()
also
function aa(b1,...others){
console.log(b1,"",others);
}
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