TypeScript functions with Generic Constraints return specific values rather than just types

function createGenericCoordinates<Type extends number | string>(
  x: Type,
  y: Type
) {
  return { x, y };
}

const genericCoordinates = createGenericCoordinates(1, 2);

// Error (TS2322)
// Type 3 is not assignable to type 1 | 2
genericCoordinates.x = 3;

Is there a way to modify this function so that both x and y can only be of type number or string regardless of the values passed as arguments (like in the scenario of 1|2 here)? Removing "extends number | string" allows it to work, but then other types might be permitted. This was tested using TS version 5.1.6.

Answer №1

TypeScript employs a variety of heuristic rules to determine whether a string or numeric literal like "a" or 2 should be assigned a specific literal type such as "a" or 2, or if it should receive an equivalent widened type like string or number. These rules have been proven effective in numerous real-world coding scenarios, although they may not always align perfectly with everyone's expectations.

These rules were predominantly featured and explained in the microsoft/TypeScript#10676 resource. Specifically, "during type argument inference for a call expression, the inferred type for a type parameter T is widened to its widened literal type when [...] T has no constraint or its constraint does not encompass primitive or literal types". Thus, in the context of a generic function:

function createGenericCoordinates<T extends number | string>(
    x: T, y: T
) { return { x, y }; }

the type parameter T carries a constraint that includes the primitive types string and number; thus, the type argument for T will not undergo widening.

To modify this behavior, one potential approach would involve eliminating the constraint from T and structuring the remainder of your call signature to enforce the desired constraint. For example:

function createGenericCoordinates<T>(
    x: T & (string | number), y: T & (string | number)) {
    return { x, y };
}

By doing so, T becomes unconstrained leading to widening upon inference of T. When invoking createGenericCoordinates(x, y), the compiler infers T from the type of x, ensuring that both x and y are assignable to the intersection T & (string | number). Any inconsistency will result in an error:

createGenericCoordinates(true, false); // error!
// --------------------> ~~~~
// function createGenericCoordinates<boolean>(x: never, y: never);

createGenericCoordinates({}, {}); // error!
// --------------------> ~~
// function createGenericCoordinates<{}>(x: string | number, y: string | number);

The compiler rejects true due to

boolean & (string | number)</code reducing to <code>never
, and {} being rejected because of
{} & (string | number)</code which reduces to <code>string | number
.

When calling the function with two strings or two numbers, there won't be any errors, and the lack of widening provides the intended outcomes:

createGenericCoordinates(1, 2);
// function createGenericCoordinates<number>(x: number, y: number);

createGenericCoordinates("a", "b");
// function createGenericCoordinates<string>(x: string, y: string);

Playground link to code

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