Ways to specify a type to require only a single property implementation from another interface

Consider the following scenario with an interface:

interface ITest {
    a: number;
    b: string;
}

In this case, the goal is to create an implementation where a function only requires an object that contains a specific subset of properties from the defined interface. For example, it may only need the a property. Initial attempts at achieving this yielded the following code snippet:

type WithOnly<T, K extends keyof T> = {
    [K in keyof T]: T[K];
}

export const f = (x: WithOnly<ITest, 'a'>) => settings.a * 2;

However, upon testing, the compiler flagged an issue where it expected the input parameter x to also contain the b property. Is there a workaround to successfully implement this requirement?

Answer №1

Getting close! To isolate only the properties specified in K, use [P in K]: T[P];


type WithSelected<T, K extends keyof T> = {
    [P in K]: T[P];
}

Try it out.

An alternative is to simply utilize Pick<ITest, 'a'> as it accomplishes the same task:

interface ITest {
    a: number;
    b: string;
}
export const f = (x: Pick<ITest, 'a'>) => x.a * 2;

f({ a: 1 })

Give it a go!

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