What is the best way to include a Typescript declaration for a Knockout extender that enhances the functionality of an observable by adding additional

I am facing a challenge with incorporating a knockout extender into a typescript file, struggling to properly declare it.

The extender is in javascript, and I need to utilize it from within a typescript file (as the project consists of both javascript and typescript). However, defining the extender has been elusive. Referencing this question, I attempted to enhance the KnockoutExtenders interface as shown below:

interface KnockoutExtenders {
    trackChange<T>(target: T, track: boolean): ITrackChange<T>;
}

interface ITrackChange<T> extends KnockoutObservable<T> {
    setOriginalValue(startingValue: T): void;
    resetToConfirmedValue(): void;
    setConfirmedValue(): void;
    numberChanges(): number;
}

The usage of the extender follows this structure:

class ProductTypeViewModel {
    constructor() {
        this.name.setOriginalValue('Initial value');
    }

    name = ko.observable('').extend({
        trackChange: true
    });
}

An error arises during compilation stating that this.name.setOriginalValue does not exist on type 'KnockoutObservable<string>', which is correct.

How should I define the extender so that typescript recognizes the additional methods applied to the observable (transforming it from a KnockoutObservable<string> to an ITrackChange<string>)?

(While perhaps not vital, here is a brief explanation of the extender: The extender tracks changes made to an observable, providing the option to accept or cancel them. This allows for displaying a current value using the observable, while enabling users to edit the value without actually changing it until they confirm the modifications. If changes are canceled, no actual alterations occur.)

Answer №1

Check out this example:

interface KnockoutObservable<T> extends Observable<T> {
  setInitialContent(param: string): void;
}

class ProductTypeViewModel {
    private title: KnockoutObservable<string>;

    constructor() {
        this.title.setOriginalValue('Default text');
    }
}

Answer №2

One way I've found to work around the typescript errors is by manually casting the type of the observable in this manner.

name = ko.observable('').extend({
    trackChange: true
}) as ITrackChange<string>;

It would be preferable to have a system in place for registering it so that the cast isn't necessary each time an observable is extended. However, until then, manual intervention will suffice. If there are better solutions out there, I'm willing to consider and accept them. (If using this method is deemed flawed, please provide feedback as to why - constructive criticism is always welcome!)

Keep in mind, when dealing with observables that have multiple extenders, you can use intersection types to display all relevant interfaces, as demonstrated in this response to another query:

name = ko.observable(false).extend({
    trackChange: true,
    logChange: true
}) as ITrackChange<boolean> & ILogChange<boolean>;

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