What is the correct way to set the default function parameter as `v => v` in JavaScript?

function customFunction<T, NT extends Record<string, string | number | boolean>>(
  data: T,
  normalize?: (data: T) => NT,
) {
  const normalizedData = normalize ? normalize(data) : {};

  return Object.keys(normalizedData);
}

customFunction(10, (v) => v);
// Error(Type 'number' is not assignable to type 'Record<string, string | number | boolean>')
// This behavior is CORRECT

customFunction(10, (data) => ({ data }));
// No error
// This behavior is CORRECT

customFunction({ data: 10 }, (v) => v);
// No error
// This behavior is CORRECT

function adjustedFunction<T, NT extends Record<string, string | number | boolean>>(
  data: T,
  normalize: (data: T) => NT = (v) => v, 
   // ERROR: Type 'T' is not assignable to type 'NT'.
   // 'NT' could be instantiated with an arbitrary type which could be unrelated to 'T'
) {
  const normalizedData = normalize(data);

  return Object.keys(normalizedData);
}

adjustedFunction(10); 
// no error
// This behavior is INCORRECT, should throw an error

adjustedFunction(10, (data) => ({ data }));
// WORKS
// This behavior is CORRECT

adjustedFunction({ data: 10 });
// WORKS
// This behavior is CORRECT

The function customFunction has been adapted to meet the requirement of having the normalize parameter optional with a default value. The default value for normalize is set to an empty object if it is not provided.

To rewrite adjustedFunction to fit the requirements, conditional typing and default values can be used appropriately to handle different scenarios and ensure correct behavior.

Answer №1

After receiving input from @spender, I managed to come up with a solution.

type ChooseType<A, B> = A extends B ? A : never;

function customFunction<S extends Record<string, string | number | boolean>>(
  inputData: S,
): string[];
function customFunction<S, NS extends Record<string, string | number | boolean>>(
  inputData: S,
  transform: (inputData: S) => NS,
): string[];
function customFunction<S, NS extends Record<string, string | number | boolean>>(
  inputData: S, 
  transform: (inputData: S) => NS = (val) => val as ChooseType<S, NS>
) {
  const transformedData = transform(inputData);

  return Object.keys(transformedData);
}

Despite implementing my ChooseType, I still feel there is room for improvement. Any suggestions are welcome.

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