What is the reason behind a tuple union requiring the argument `never` in the `.includes()` method?

type Word = "foo" | "bar" | "baz";

const structure = {
  foo: ["foo"] as const,
  bar: ["bar"] as const,
  baX: ["bar", "baz"] as const,
};

const testFunction = (key: keyof typeof schema, word: Word) => {
  const list = schema[key]
  list.includes(word);
//               ^
// TS2345: Argument of type 'string' is not assignable to parameter of type 'never'.    
//  Type 'string' is not assignable to type 'never'
}

Playground link

What is causing this issue? It appears quite silly to me... or am I overlooking something? How can I address this in a logical manner? Should I simply assert to never, or are there unforeseen drawbacks?

Answer №1

Exploring the different varieties, let's dive into some types we encounter.

array: readonly ["foo"] | readonly ["bar"] | readonly ["bar", "baz"]

When using the include method on a T[], it requires an argument of type T, matching the list's correct type. In Typescript, questioning whether a string is within an array of integers is considered ill-typed due to its likelihood of being mistakenly written in the first place.

This isn't just an ordinary array; it's a union. To invoke a method on a union, that method must be compatible with all options within the union.

The array ["foo"] has an include method accepting a "foo" as its argument (representing a literal string "foo"). Similarly, the array ["bar"] supports an include method expecting a "bar" argument, and the array ["bar", "baz"] includes an include method for elements of the type "bar" | "baz".

However, since it's uncertain which specific option exists within the union, the include call must accept input valid for all three variations. Hence, the argument should belong to the intersection type:

"foo" & "bar" & "baz"

No single string is fitting for all these conditions, rendering this type uninhabited or effectively never. As a result, calling include in a type-safe manner becomes unfeasible.

You may resort to any-casting to work around such constraints, albeit sacrificing type safety. Alternatively, preserving type integrity proves more beneficial. Instead of relying solely on Typescript's highly-specific inference, explicitly declare the type you desire:

array : readonly Word[]

This declaration actually serves as a valid supertype encompassing the previously mentioned options. By providing an explicit type hint through annotation, like so:

const array: readonly Word[] = schema[schemaKey]

It's important to note that this adjustment does not entail a typical cast instructing the type system to stay quiet. The declared readonly Word[] remains a legitimate supertype compared to the inferred literal union type. Therefore, this code passes validation while upholding type safety, requiring nothing but clarity regarding our intentions to aid the compiler.

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