What is the reason behind Flow's reluctance to infer the function type from its return value?

I was anticipating the code to undergo type checking within Flow just like it does within TypeScript:

var onClick : (() => void) | (() => boolean);
onClick = () => { return true; }

However, I encountered this error instead:

4: onClick = () => { return true; }
             ^ function. Could not decide which case to select
3: var onClick : (() => void) | (() => boolean);
                  ^ union type

Does this design decision have a specific name, and what is the rationale behind it?

Can we prompt the Flow checker to deduce the return type of a function from its return statements?

Answer №1

To solve this issue, you have two options:

type FuncV = () => void;
type FuncB = () => boolean;
var onClick: FuncV | FuncB;

onClick = (() => { return true; }: FuncB);

Alternatively, you can use an existential type like this:

type Func<T: (void | string)> = () => T;
var f: Func<*>;

f = () => { return "hello"; };
var msg = f() + " world!";  // type checks against return value above

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