Having difficulty casting the parameter type from Array.find() in TypeScript

In my codebase, I am dealing with the OrganisationInterface type:

export declare interface OrganisationInterface {
    documents?: {
        [documentType: OrganisationDocumentTypesList]: { // enum
            id: string;
            name: string;
            src?: string;
        }
    };
}

When working in my executable code, this is what I have:

const organisation = { ...<OrganisationInterface>organisationSnap.data(), id: organisationId }

// Here are a few attempts that I made to handle the 'record' variable type inference
const documentRecord1 = Object.values(organisation?.documents ?? {}).find((record) => record.id! === fileId)

const documentRecord2 = Object.values(organisation?.documents ?? {}).find((<OrganisationInterface['documents']>record) => record.id! === fileId)

const documentRecord3 = Object.values(organisation?.documents ?? {}).find((record) => (<OrganisationInterface['documents']>record).id! === fileId)

const documentRecord4 = Object.values(organisation?.documents ?? {}).find((record) => (<Required<OrganisationInterface>['documents']>record).id! === fileId)

I am perplexed as to why TypeScript refuses to allow me to specify the type of the record variable returned by the Array.find() function. Any insights?

Answer №1

Upon examining the definition of Object.values:

values<T>(o: { [s: string]: T } | ArrayLike<T>): T[];
, it is evident that the type is automatically determined.

You have the option to create an alias for your indexed type:

type Values<T> = T[keyof T];
type Document = Values<NonNullable<OrganisationInterface['documents']>>

From there, you can utilize that return type in the following manner:

const documentRecord = Object.values<MyDocument>(organisation?.documents ?? {}).find((record) => record?.id === fileId)

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