Retrieve items from the type group [T, V] where U is not included, and [U, any]. T should be a union type in the context

Some time ago, I shared my query on Inferring the shape of the result from Object.fromEntries() in TypeScript. The response I received seemed to work well for me until a couple of days back.

declare global {
  interface ObjectConstructor {
    fromEntries<
      A extends ReadonlyArray<readonly [PropertyKey, any]>
    >(array: A): { [K in A[number][0]]: Extract<A[number], readonly [K, any]>[1] }
  }
}

This approach functions smoothly when A[number][0] is mapped to precisely one type in each element. However, it encounters an issue if you specify that the first element of each tuple is a union type.

const x = Object.fromEntries(
  [['a', 1], ['b', 2], ['c', 'foo']] as (['a' | 'b', number] | ['c', string])[]
);
// typeof x = { a: never, b: never; c: string; }

The problem arises because K will always be either 'a' or 'b', and given that 'a' | 'b' does not extend 'a', it results in failure. I am aware of how to split a tuple of unions into unions of tuples, but only if the type of the second element remains consistent across all tuples, which may not be the case here.

Is there a way to adjust the definition of Object.fromEntries() to accommodate keys with union types?

TS Playground

Answer №1

Solved the problem (I believe)! Instead of using Extract, I found success by utilizing intersections.

declare global {
  interface ObjectConstructor {
    fromEntries<
      A extends ReadonlyArray<readonly [PropertyKey, any]>
    >(array: A): { [K in A[number][0]]: (A[number] & readonly [K, unknown])[1] };
  }
}

This approach has proven effective for all of my test scenarios.

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